加勒比久久综合,国产精品伦一区二区,66精品视频在线观看,一区二区电影

合肥生活安徽新聞合肥交通合肥房產生活服務合肥教育合肥招聘合肥旅游文化藝術合肥美食合肥地圖合肥社保合肥醫院企業服務合肥法律

EBU6335代寫、Java,c/c++程序語言代做

時間:2024-03-02  來源:合肥網hfw.cc  作者:hfw.cc 我要糾錯



EBU6335 2022/23
Question 1
a) Describe entry in the context of digital system design. Also explain how VHDL is used in the entry
process.
[5 marks]
b) The following is an incomplete VHDL model the so-called Or-And-Invert (OAI) gate (Boolean function Y = (A + B) · C), possibly with some syntax errors.
[8 marks]
entity OAI21 is
port (
A B C: in std_logic
Y: out std_logic
)
end
architecture is
Y = ~(A + B * C)
end architecture
i) Copy, correct and complete the VHDL code.
(5 marks)
ii) Suggest the output of the gate if inputs are A = 0, B = C = 1.
(3 marks)
c) In a signed binary addition S = A + B, it is known that A > 0 and B < 0.
[10 marks]
i) Explain whether there will be a carry in such an addition or not.
(3 marks)
ii) How is signed number represented?
(2 marks)
iii) Suppose the following full adder block FA is given as a component, write the VHDL architecture (no
need to provide the entity) for a 48-bit binary subtractor that takes A and B and gives S. You can
ignore carry in and out for your answer.
entity FA is
port (X, Y, Cin : in std_logic;
S, Cout : out std_logic);
end FA;
(5 marks)
Page 2 of 8
EBU6335 2022/23
Question 2
a) Explain briefly how a D flip-flop can be constructed using D latch(es).
[4 marks]
b) Figure 1 shows a sequential block constructed by a 2-to-1 multiplexer (MUX) and a positive-edge
trigged D flip-flop. This can be used to build a shift register.
[11 marks]
Figure 1: Sequential Block built by a MUX and a Flip-flop
i) If it is given that inverter has an area of 2 units and any 2-input logic gate has an area of 3 units,
estimate the area of the block.
(3 marks)
ii) Design and construct a 4-bit left shift register (i.e. towards MSB) using the block in Figure 1:
input(s): shift in bit X, shift control Shif t (active-high)
output(s): counter outputs Y = (MSB)Y3Y2Y1Y0(LSB)
Illustrate your design using a diagram (with proper annotations)
(5 marks)
iii) Is your design in ii) synchronous? Explain why.
(3 marks)
c) You are asked to design an add-2 synchronous counter that counts in 0, 2, 4,... numerically.
[8 marks]
i) Discuss a general strategy to design a synchronous counter
(4 marks)
ii) Write the VHDL architecture for the required add-2 synchronous counter with an asynchronous reset,
based on the following entity.
Your answer should use NO components.
entity SyncCountBy2 is
port (RST: in std_logic; -- asynchronous reset
CLK: in std_logic; -- clock signal
Q: out std_logic_vector(7 downto 0));
end SyncCountBy2;
(4 marks)
Page 3 of 8
EBU6335 2022/23
Question 3
a) A mealy finite state machine is used to automate a vending machine. The machine dispenses a bottle
of water after ≥ (greater than or equal to) 1 Yuan (=10 Jiao) is deposited. There is a single slot
through which to insert Yuan and Jiao. One cannot insert Yuan and Jiao at the same time. One
cannot insert any other coins or notes. The machine does not issue change. Figure 2 shows the state
transition diagram for the system.
[10 marks]
Figure 2: State transition diagram for a vending machine which dispenses bottles of water
i) State one difference between a synchronous state machine and an asynchronous state machine?
(1 marks)
ii) How many flip-flops in minimum are required to implement this state machine?
(1 marks)
iii) Part of the VHDL code used to implement the state machine is given below. Complete the code.
(8 marks)
entity mealy is
Port ( clk, rst : in STD_LOGIC;
1_Yuan, 5_Jiao : in STD_LOGIC;
dispense_water : out STD_LOGIC);
end mealy;
architecture Behavioral of mealy is
type state is (st0, st1);
signal present_state , next_state: state;
begin
syncronous_process: process (clk)
begin
if rising_edge(clk) then
if (rst = '1') then
present_state <= st0;
else
present_state <= next_state;
end if;
end if;
end process;
next_state_and_output_decoder: process(present_state , din)
begin
dispense_water <= '0';
next_state <= present_state;
case (present_state) is
-- your answers begin here
Page 4 of 8
EBU6335 2022/23
-- ...
-- ...
end case;
end process;
end Behavioral;
b) Consider the incomplete first-in first-out (FIFO) buffer shown in Figure 3. The 4-bit up counter is included to generate full and empty control signals. Prepare the VHDL architecture without any component
for the part circled in red.
[7 marks]
Figure 3: Block diagram for a First-in first-out buffer
c) Consider the DRAM cell, shown in Figure 4.
Figure 4: DRAM cell
The following sequence of events occurs. Explain whether this will lead to a ‘1’ being stored in the
cell. If not please explain what changes/additions are required and why.
[3 marks]
Step 1: The row input is set to 5V to represent the ‘1’ that will be written to the cell.
Step 2: Next the transistor must be turned on by setting the row input to 5V.
Step 3: The voltage on the capacitor will then increase until it reaches 5V.
Step 4: The transistor must remain turned on in order to trap the stored charge.
Page 5 of 8
EBU6335 2022/23
d) Figure 5 shows a number of tristate logic gates connected to a common bus line. Copy the diagram
and add the missing inputs and outputs to the points labelled A, B, C on the diagram.
[3 marks]
Figure 5: Tristate logic circuit
Page 6 of 8
EBU6335 2022/23
Question 4
a) The following algorithm is used to compare two 5-bit binary numbers and count the number of
corresponding bits that differ between them.
[13 marks]
i=0
Number_of_Bits = 5
while (i < Number_of_Bits) {
i=i+1
if (Binary_Number_1(i) =/ Binary_Number_2(i)){
j=j+1
}
}
output = j;
You are given a datapath as shown in Figure 6. The control signals are circled with their respective
bit positions in the control word, e.g. LD for R0 is bit 1 of the control word. RX.0 denotes the bit 0
(LSB) of the value stored in register RX and the shifter shifts value exactly 1 bit to the left (towards
LSB).
Figure 6: A Datapath with 5 registers
i) Based on the datapath shown in Figure 6, express the algorithm in RTL/RTN. You should generate
a done signal when the algorithm finishes.
(7 marks)
ii) Derive the control words (13; 12; ... ; 1; 0) for your algorithm.
(6 marks)
b) Consider the following number 5.37510. Express this number using a 10-bit binary number having
same number of bits for the integer and fractional parts.
[4 marks]
c) We wish to form the following product: 710 ×310. Let M = 710 and Q = 310. Use Booth’s Algorithm
to calculate the result. Show all workings.
[6 marks]
Page 7 of 8
EBU6335 2022/23
Question 5
ASCII code is a character encoding using exactly eight bits. In digital communications for ASCII code,
a start bit S (1→ 0) and a stop bit P (0→ 1) are attached to the beginning and the end of the character bit
stream respectively. For example, character A is encoded and transmitted as S01000001P.
You are now required to build a digital system for communications for 8-bit ASCII code.
Based on your design experience from the course project, discuss your approach in (i) designing an asynchronous ASCII code transmitter and receiver, and (ii) modelling and implementing the system.
[8 marks]
While your answer can be expressed in various formats (e.g. text, flow chart, block diagram) in your own
choice, that should cover BOTH aspects of the system, as explained above.
請加QQ:99515681  郵箱:99515681@qq.com   WX:codehelp 

掃一掃在手機打開當前頁
  • 上一篇:代寫股票指標 代編股票公式
  • 下一篇:COMP9021代做、Python程序語言代寫
  • 無相關信息
    合肥生活資訊

    合肥圖文信息
    2025年10月份更新拼多多改銷助手小象助手多多出評軟件
    2025年10月份更新拼多多改銷助手小象助手多
    有限元分析 CAE仿真分析服務-企業/產品研發/客戶要求/設計優化
    有限元分析 CAE仿真分析服務-企業/產品研發
    急尋熱仿真分析?代做熱仿真服務+熱設計優化
    急尋熱仿真分析?代做熱仿真服務+熱設計優化
    出評 開團工具
    出評 開團工具
    挖掘機濾芯提升發動機性能
    挖掘機濾芯提升發動機性能
    海信羅馬假日洗衣機亮相AWE  復古美學與現代科技完美結合
    海信羅馬假日洗衣機亮相AWE 復古美學與現代
    合肥機場巴士4號線
    合肥機場巴士4號線
    合肥機場巴士3號線
    合肥機場巴士3號線
  • 短信驗證碼 目錄網 排行網

    關于我們 | 打賞支持 | 廣告服務 | 聯系我們 | 網站地圖 | 免責聲明 | 幫助中心 | 友情鏈接 |

    Copyright © 2025 hfw.cc Inc. All Rights Reserved. 合肥網 版權所有
    ICP備06013414號-3 公安備 42010502001045

    三级不卡在线观看| 狠色狠色综合久久| 国产精品a久久久久| 鲁大师成人一区二区三区| 精品久久久久久久久久久下田| 日本视频中文字幕一区二区三区| 欧美xxxx中国| 2023国产精品久久久精品双| eeuss鲁片一区二区三区| 一区二区三区在线电影| 男人最爱成人网| 欧美裸体在线版观看完整版| 国产日韩一区二区三免费高清| 日本aⅴ亚洲精品中文乱码| 日韩国产专区| 喷白浆一区二区| 91久久久久| 视频小说一区二区| 国产美女亚洲精品7777| 99综合久久| 亚洲国产黄色| 精品美女一区| 亚洲伦乱视频| 国产精品国内免费一区二区三区| 亚洲精品在线观看91| 久久久成人网| 国产欧美啪啪| 精品国产一区二区三区性色av| 99国内精品久久久久| 美女视频网站黄色亚洲| 国产成人免费9x9x人网站视频| 久久亚洲精品伦理| 好吊日精品视频| 亚洲高清毛片| 国模吧视频一区| 99久久精品费精品国产| 国产精品对白久久久久粗| 日韩精品一区二区三区中文在线 | 99热播精品免费| 成人亚洲欧美| 中文一区一区三区高中清不卡免费| 久久综合影视| 蜜臀91精品一区二区三区| 蜜桃伊人久久| 日本一区二区在线看| 视频一区二区三区入口| 麻豆视频在线看| 久久综合av| 亚洲天堂男人| 91久久高清国语自产拍| 国模吧视频一区| 天天色天天射综合网| 九九久久精品| 一本色道88久久加勒比精品| 99亚洲视频| 久久亚洲一区| 正在播放日韩精品| 亚洲综合在线电影| 亚洲国产天堂| 麻豆国产欧美一区二区三区| 国产精品theporn| 国产精品一区二区精品| 国产一区二区观看| 51精品国产| 久久久青草婷婷精品综合日韩| 久久精品影视| 99在线精品免费视频九九视| 免费成人在线观看视频| 麻豆视频在线看| 本网站久久精品| 日本少妇一区二区| 亚洲制服一区| 伊人精品综合| 久久亚洲成人| 亚洲欧美日韩视频二区| 国产自产自拍视频在线观看| 成人啊v在线| 国产精品地址| 日韩精品一区国产| 伊人春色之综合网| 午夜综合激情| 欧美日韩五区| av在线精品| 丁香一区二区| 日韩一区二区久久| 在线看片福利| 麻豆91在线观看| 日本精品在线播放| 免费观看久久av| 男男视频亚洲欧美| 亚洲a成人v| 国产日产精品一区二区三区四区的观看方式 | 911亚洲精品| 亚洲国产成人精品女人| 欧美男人天堂| 欧美国产先锋| 国产精品高潮呻吟久久久久 | 波多视频一区| 日韩精品电影一区亚洲| 日韩av中文字幕一区二区三区| 久久国产精品亚洲人一区二区三区 | 中文欧美日韩| 欧美gv在线观看| 欧美三级一区| 一本久久青青| 久久天堂av| 亚洲欧美校园春色| 欧美裸体在线版观看完整版| sm久久捆绑调教精品一区| 欧美日韩亚洲国产精品| 久久久久久9| 另类专区亚洲| 国产精品一级在线观看| 欧美一区二区性| av免费在线一区| 日韩深夜福利| 性欧美暴力猛交另类hd| 亚洲区国产区| 99久久夜色精品国产亚洲狼| 视频在线不卡免费观看| 综合天堂av久久久久久久| 色爱av综合网| 日韩国产一区二区三区| 亚洲黄色录像| 日韩中文字幕一区二区三区| 亚洲精品婷婷| 欧美色图一区| 日本在线一区二区| 日本a级不卡| 免费成人在线电影| 日韩欧美激情电影| 色综合久久网| 精品国产一区二| 蜜臀av一区二区| 亚洲人挤奶视频| 免费在线视频一区| 亚洲福利网站| 色婷婷亚洲mv天堂mv在影片| 精品一区二区三区中文字幕| 最新成人av网站| 亚洲午夜精品一区 二区 三区| 欧美成人综合| 亚洲人成人一区二区三区| 制服丝袜日韩| 三级久久三级久久久| 欧美1区2区| 亚洲国产一区二区精品专区| 91久久电影| 麻豆精品一区二区三区| 亚洲电影在线一区二区三区| 欧美日韩在线大尺度| 在线一区电影| 成人在线视频国产| 老鸭窝亚洲一区二区三区| 国产精品午夜一区二区三区| 人人超碰91尤物精品国产| 日韩电影在线一区二区三区| 国产精品久久占久久| 亚洲2区在线| 韩国精品视频在线观看| 天堂资源在线亚洲| 麻豆一区二区三| 在线视频精品| 日韩美女毛片| 亚洲精品aaa| 欧美日韩四区| 偷拍视屏一区| 亚洲第一av| 婷婷成人综合| 高清久久精品| 亚洲欧美se| 一区三区在线欧| 亚洲黄色录像| 精品视频在线一区二区在线| 韩日一区二区三区| 国产伦精品一区二区三区视频| 欧美日韩在线观看首页| 三级小说欧洲区亚洲区| 国色天香一区二区| 手机av在线| 久久国产亚洲精品| 欧美午夜网站| 日本肉肉一区| 国产精品日本欧美一区二区三区| 午夜欧洲一区| 一区二区三区高清视频在线观看| 樱桃成人精品视频在线播放| 视频一区日韩精品| 日韩三区四区| 视频一区中文字幕国产| 精品日韩在线| 国产麻豆精品久久| 先锋影音网一区二区| 老**午夜毛片一区二区三区| jizz性欧美23| 电影一区中文字幕| 国产在视频一区二区三区吞精| 久久香蕉精品| 婷婷综合伊人| 精品久久不卡|