加勒比久久综合,国产精品伦一区二区,66精品视频在线观看,一区二区电影

合肥生活安徽新聞合肥交通合肥房產生活服務合肥教育合肥招聘合肥旅游文化藝術合肥美食合肥地圖合肥社保合肥醫院企業服務合肥法律

EIE553代做、代寫EIE553程序語言
EIE553代做、代寫EIE553程序語言

時間:2025-03-02  來源:合肥網hfw.cc  作者:hfw.cc 我要糾錯



EIE553 Lab 1 1
EIE553 Security in Data Communication
Lab 1: RSA Public-Key Encryption
and Signatures
Report Deadline: 11:59 pm, Mar. 2, 2025 HKT
(Credits: SEED Labs 2.0 by Prof. Du, Wenliang)
1 Overview
RSA (Rivest–Shamir–Adleman) is one of the first public-key cryptosystems and is widely used for secure 
communication. The RSA algorithm first generates two large random prime numbers, and then use them 
to generate public and private key pairs, which can be used to do encryption, decryption, digital signature 
generation, and digital signature verification. The RSA algorithm is built upon number theories, and it can 
be quite easily implemented with the support of libraries.
The learning objective of this lab is for students to gain hands-on experiences on the RSA algorithm. 
From lectures, students should have learned the theoretic part of the RSA algorithm, so they know math ematically how to generate public/private keys and how to perform encryption/decryption and signature 
generation/verification. This lab enhances student’s understanding of RSA by requiring them to go through 
every essential step of the RSA algorithm on actual numbers, so they can apply the theories learned from 
the class. Essentially, students will be implementing the RSA algorithm using the C program language. The 
lab covers the following security-related topics:
• Public-key cryptography
• The RSA algorithm and key generation
• Big number calculation
• Encryption and Decryption using RSA
• Digital signature
• X.509 certificate
Lab environment: The SEED Lab series (including this one) has been tested on the SEED Ubuntu 20.04
VM. In our lab at CF105, the VM is pre-built and you can connect to it via:
1. Run Hyper-V Virtual Machine Connection
2. Select “SEED Ubuntu 20.04”
EIE553 Lab 1 2
3. Click Start
4. Input username: seed and password: dees
NOTE: The Ubuntu 20.04 VM is not strictly necessary. You can complete or implement the tasks 
below using your preferred IDE (on your own PC) and programming language (though C/C++
is recommended).
NOTE: The PC might REBORN AFTER REBOOT AND SHARED WITH OTHER STUDENTS. 
Save your work in an external drive and back up your files before rebooting or shutting down.
You also can download a pre-built image from the SEED website, and run VM on your own PC.
The setup can be found: https://seedsecuritylabs.org/labsetup.html (for either Intel/Apple/AMD CPU)
How to build SEED VM: https://github.com/seed-labs/seed-labs/blob/master/manuals/vm/seedvm-from scratch.md
A step-by-step guideline (prepared by TAs) on how to build SEED VM on a Windows PC has been 
uploaded to Blackboard for your reference.
2 Background
The RSA algorithm involves computations on large numbers. These computations cannot be directly con ducted using simple arithmetic operatorsin programs, because those operators can only operate on primitive 
data types, such as 32-bit integer and 64-bit long integer types. The numbers involved in the RSA algorithms 
are typically more than 512 bits long. For example, to multiple two 32-bit integer numbers a and b, we just
EIE553 Lab 1 3
// Assign a value from a decimal number string
BN_dec2bn(&a, "12345678901112231223");
// Assign a value from a hex number string
BN_hex2bn(&a, "2A3B4C55FF77889AED3F");
// Generate a random number of 128 bits 
BN_rand(a, 128, 0, 0);
// Generate a random prime number of 128 bits 
BN_generate_prime_ex(a, 128, 1, NULL, NULL, NULL);
void printBN(char *msg, BIGNUM * a)
{
// Convert the BIGNUM to number string 
char * number_str = BN_bn2dec(a);
// Print out the number string 
printf("%s %s\n", msg, number_str);
// Free the dynamically allocated memory 
OPENSSL_free(number_str);
}
need to use a*b in our program. However, if they are big numbers, we cannot do that any more; instead, 
we need to use an algorithm (i.e., a function) to compute their products.
There are several libraries that can perform arithmetic operations on integers of arbitrary size. In this 
lab, we will use the Big Number library provided by openssl. To use this library, we will define each big 
number as a BIGNUM type, and then use the APIs provided by the library for various operations, such as 
addition, multiplication, exponentiation, modular operations, etc.
2.1 BIGNUM APIs
All the big number APIs can be found from https://linux.die.net/man/3/bn. In the following, 
we describe some of the APIs that are needed for this lab.
• Some of the library functions requires temporary variables. Since dynamic memory allocation to cre ate BIGNUMs is quite expensive when used in conjunction with repeated subroutine calls, a BN CTX 
structure is created to holds BIGNUM temporary variables used by library functions. We need to 
create such a structure, and pass it to the functions that requires it.
BN_CTX *ctx = BN_CTX_new()
• Initialize a BIGNUM variable.
BIGNUM *a = BN_new()
• There are a number of ways to assign a value to a BIGNUM variable.
• Print out a big number.
EIE553 Lab 1 4
BN_sub(res, a, b);
BN_add(res, a, b);
/* bn_sample.c */ 
#include <stdio.h>
#include <openssl/bn.h> 
#define NBITS 256
void printBN(char *msg, BIGNUM * a)
{
/* Use BN_bn2hex(a) for hex string
* Use BN_bn2dec(a) for decimal string */ 
char * number_str = BN_bn2hex(a); 
printf("%s %s\n", msg, number_str);
OPENSSL_free(number_str);
}
int main ()
{
BN_CTX *ctx = BN_CTX_new();
BIGNUM *a = BN_new(); 
BIGNUM *b = BN_new(); 
BIGNUM *n = BN_new(); 
BIGNUM *res = BN_new();
• Compute res = a −b and res = a + b:
• Compute res = a ∗b. It should be noted that a BN CTX structure is need in this API.
BN_mul(res, a, b, ctx)
• Compute res = a ∗b mod n:
BN_mod_mul(res, a, b, n, ctx)
• Compute res = ac mod n:
BN_mod_exp(res, a, c, n, ctx)
• Compute modular inverse, i.e., given a, find b, such that a ∗ b mod n = 1. The value b is called 
the inverse of a, with respect to modular n.
BN_mod_inverse(b, a, n, ctx);
2.2 A Complete Example
We show a complete example in the following. The program can be found from the Labsetup.zip file 
that you can download from the lab’s webpage. In this example, we initialize three BIGNUM variables, a, 
b, and n; we then compute a ∗b and (ab mod n).
EIE553 Lab 1 5
$ vim bn_sample.c
$ gcc bn_sample.c -lcrypto -o output
$ ./output
Compilation. We can use the following command to compile bn_sample.c (the character after - is the 
letter £, not the number 1; it tells the compiler to use the crypto library).
Click “Open in Terminal”
Create bn_sample.c file
Paste your code into the file, Press Esc on your keyboard, input “: wq” to save file and quit.
Complie bn_sample.c
Run bn_sample.c
// Initialize a, b, n
BN_generate_prime_ex(a, NBITS, 1, NULL, NULL, NULL); 
BN_dec2bn(&b, "273489463796838501848592769467194369268");
BN_rand(n, NBITS, 0, 0);
// res = a*b 
BN_mul(res, a, b, ctx);
printBN("a * b = ", res);
// res = aˆb mod n 
BN_mod_exp(res, a, b, n, ctx); 
printBN("aˆc mod n = ", res);
return 0;
}
EIE553 Lab 1 6
p = F7E75FDC469067FFDC4E847C51F452DF
q = E85CED54AF57E53E092113E62F436F4F 
e = 0D88C3
$ python3 -c ’print("A top secret!".encode("utf-8").hex())’
4120746f702073656372657421
3 Lab Tasks
NOTE: You must explicitly disclose the use of any GenAI tools (e.g., ChatGPT and DeepSeek) if utilized 
in completing the tasks below.
3.1 Task 1: Deriving the Private Key (20 marks)
Let p, q, and e be three prime numbers. Let n = p*q. We will use (e, n) as the public key. Please 
calculate the private key d. The hexadecimal values of p, q, and e are listed in the following. It should be 
noted that although p and q used in this task are quite large numbers, they are not large enough to be secure. 
We intentionally make them small for the sake of simplicity. In practice, these numbers should be at least 
512 bits long (the one used here are only 128 bits).
Hint: The private key d (which is multiplicative inverse of e mod n) can be computed via the extended Euclidean 
algorithm (introduced in Lecture 4). The pseudocode is
Input: 
 - Public key (N, e)
 - Prime factors p and q of N (N = pq)
Output:
 - Private key d
Steps:
1. Compute ϕ(N) = (p - 1) * (q - 1) // Euler's totient function
2. Use the Extended Euclidean Algorithm to find d such that:
 (e * d) ≡ 1 mod ϕ(N)
Extended Euclidean Algorithm:
 Function ExtendedEuclidean(a, b):
 If b == 0:
 Return (a, 1, 0) // gcd(a, b) = a, and coefficients x = 1, y = 0
 Else:
 (gcd, x1, y1) = ExtendedEuclidean(b, a mod b)
 x = y1
 y = x1 - (a // b) * y1
 Return (gcd, x, y)
3. (gcd, d, _) = ExtendedEuclidean(e, ϕ(N))
4. If gcd != 1:
 Return "No modular inverse exists (e and ϕ(N) are not coprime)"
 Else:
 Ensure d is positive by computing d = d mod ϕ(N)
 Return d
3.2 Task 2: Encrypting a Message (20 marks)
Let (e, n) be the public key. Please encrypt the message "A top secret!" (the quotations are not 
included). We need to convert this ASCII string to a hex string, and then convert the hex string to a BIGNUM 
using the hex-to-bn API BN hex2bn(). The following python command can be used to convert a plain 
ASCII string to a hex string.
SEED Labs 2.0 VM (Ubuntu 20.04.2 LTS):
SEED Labs 1.0 VM (Ubuntu 16.04 LTS):
EIE553 Lab 1 7
n = DCBFFE3E51F62E09CE7032E2677A78946A849DC4CDDE3A4D0CB81629242FB1A5
e = 010001 (this hex value equals to decimal 65537) 
M = A top secret!
d = 74D806F9F3A62BAE331FFE3F0A68AFE35B3D2E4794148AACBC26AA381CD7D30D
C = 8C0F971DF2F3672B28811407E2DABBE1DA0FEBBBDFC7DCB67396567EA1E2493F
$ python3 -c
’print(bytes.fromhex("4120746f702073656372657421").decode("utf-8"))’ 
A top secret!
M = I owe you $2000.
M = Launch a missile.
S = 643D6F34902D9C7EC90CB0B2BCA36C47FA37165C0005CAB026C0542CBDB6802F
e = 010001 (this hex value equals to decimal 65537)
n = AE1CD4DC432798D933779FBD46C6E1247F0CF1****95113AA51B450F18116115
The public keys are listed in the followings (hexadecimal). We also provide the private key d to help 
you verify your encryption result.
Requirement: In your lab report, you should change the message to "Your Name + Student ID" instead of using 
"A top secret!" in the above demo.
3.3 Task 3: Decrypting a Message (20 marks)
The public/private keys used in this task are the same as the ones used in Task 2. Please decrypt the following 
ciphertext C, and convert it back to a plain ASCII string.
You can use the following python command to convert a hex string back to to a plain ASCII string 
(works in both VM versions).
Requirement: In your lab report, you should decrypt the ciphertext of "Your Name + Student ID" instead of 
using "A top secret!" in the above demo.
3.4 Task 4: Signing a Message (20 marks)
The public/private keys used in this task are the same as the ones used in Task 2. Please generate a signature 
for the following message (please directly sign this message, instead of signing its hash value):
Please make a slight change to the message M, such as changing $2000 to $3000, and sign the modified 
message. Compare both signatures and describe what you observe.
Requirement: In your lab report, you should change the message to "Your PolyU email address" instead of 
using "I owe you $2000" in the above demo.
3.5 Task 5: Verifying a Signature (20 marks)
Bob receives a message M = "Launch a missile." from Alice, with her signature S. We know that 
Alice’s public key is (e, n). Please verify whether the signature is indeed Alice’s or not. The public key 
and signature (hexadecimal) are listed in the following:
Suppose that the signature above is corrupted, such that the last byte of the signature changes from 2F 
to 3F, i.e, there is only one bit of change. Please repeat this task, and describe what will happen to the 
verification process.
$ python -c ’print("A top secret!".encode("hex"))’
4120746f702073656372657421
EIE553 Lab 1 8
$ openssl s_client -connect www.example.org:443 -showcerts
Certificate chain
0 s:/C=US/ST=California/L=Los Angeles/O=Internet Corporation for Assigned 
Names and Numbers/OU=Technology/CN=www.example.org
i:/C=US/O=DigiCert Inc/OU=www.digicert.com/CN=DigiCert SHA2 High Assurance
Server CA
-----BEGIN CERTIFICATE-----
MIIF8jCCBNqgAwIBAgIQDmTF+8I2reFLFyrrQceMsDANBgkqhkiG9w0BAQsFADBw 
MQswCQYDVQQGEwJVUzEVMBMGA1UEChMMRGlnaUNlcnQgSW5jMRkwFwYDVQQLExB3
......
wDSiIIWIWJiJGbEeIO0TIFwEVWTOnbNl/faPXpk5IRXicapqiII=
-----END CERTIFICATE-----
1 s:/C=US/O=DigiCert Inc/OU=www.digicert.com/CN=DigiCert SHA2 High 
Assurance Server CA
i:/C=US/O=DigiCert Inc/OU=www.digicert.com/CN=DigiCert High Assurance
EV Root CA
-----BEGIN CERTIFICATE-----
MIIEsTCCA5mgAwIBAgIQBOHnpNxc8vNtwCtCuF0VnzANBgkqhkiG9w0BAQsFADBs 
MQswCQYDVQQGEwJVUzEVMBMGA1UEChMMRGlnaUNlcnQgSW5jMRkwFwYDVQQLExB3
......
cPUeybQ=
-----END CERTIFICATE-----
3.6 (Optional) Task 6: Manually Verifying an X.509 Certificate (20 marks) (Optional)
In this task, we will manually verify an X.509 certificate using our program. An X.509 contains data about 
a public key and an issuer’s signature on the data. We will download a real X.509 certificate from a web 
server, get its issuer’s public key, and then use this public key to verify the signature on the certificate.
Step 1: Download a certificate from a real web server. We use the www.example.org server in 
this document. Students should choose a different web server that has a different certificate than the 
one used in this document (it should be noted that www.example.com share the same certificate with 
www.example.org). We can download certificates using browsers or use the following command:
The result of the command contains two certificates. The subject field (the entry starting with s:) of 
the certificate is www.example.org, i.e., this is www.example.org’s certificate. The issuer field (the 
entry starting with i:) provides the issuer’s information. The subject field of the second certificate is the 
same as the issuer field of the first certificate. Basically, the second certificate belongs to an intermediate 
CA. In this task, we will use CA’s certificate to verify a server certificate.
If you only get one certificate back using the above command, that means the certificate you get is signed 
by a root CA. Root CAs’ certificates can be obtained from the Firefox browser installed in our pre-built VM. 
Go to the Edit ➔ Preferences ➔ Privacy and then Security ➔ View Certificates. Search 
for the name of the issuer and download its certificate.
Copy and paste each of the certificate (the text between the line containing "Begin CERTIFICATE" 
and the line containing "END CERTIFICATE", including these two lines) to a file. Let us call the first one 
c0.pem and the second one c1.pem.
Step 2: Extract the public key (e, n) from the issuer’s certificate. Openssl provides commands to 
extract certain attributes from the x509 certificates. We can extract the value of n using -modulus. There 
is no specific command to extract e, but we can print out all the fields and can easily find the value of e.
EIE553 Lab 1 9
$ openssl x509 -in c0.pem -text -noout
...
Signature Algorithm: sha256WithRSAEncryption 
84:a8:9a:11:a7:d8:bd:0b:26:7e:52:24:7b:b2:55:9d:ea:30:
89:51:08:87:6f:a9:ed:10:ea:5b:3e:0b:c7:2d:47:04:4e:dd:
...... 
5c:04:55:64:ce:9d:b3:65:fd:f6:8f:5e:99:39:21:15:e2:71: 
aa:6a:88:82
$ cat signature | tr -d ’[:space:]:’
84a89a11a7d8bd0b267e52247bb2559dea30895108876fa9ed10ea5b3e0bc7
......
5c045564ce9db365fdf68f5e****2115e271aa6a8882
Step 3: Extract the signature from the server’s certificate. There is no specific opensslcommand to 
extract the signature field. However, we can print out all the fields and then copy and paste the signature 
block into a file (note: if the signature algorithm used in the certificate is not based on RSA, you can find 
another certificate).
We need to remove the spaces and colons from the data, so we can get a hex-string that we can feed into 
our program. The following command commands can achieve this goal. The tr command is a Linux utility 
tool for string operations. In this case, the -d option is used to delete ":" and "space" from the data.
Step 4: Extract the body of the server’s certificate. A Certificate Authority (CA) generatesthe signature 
for a server certificate by first computing the hash of the certificate, and then sign the hash. To verify the 
signature, we also need to generate the hash from a certificate. Since the hash is generated before the 
signature is computed, we need to exclude the signature block of a certificate when computing the hash. 
Finding out what part of the certificate is used to generate the hash is quite challenging without a good 
understanding of the format of the certificate.
X.509 certificates are encoded using the ASN.1 (Abstract Syntax Notation.One) standard, so if we can 
parse the ASN.1 structure, we can easily extract any field from a certificate. Openssl has a command called 
asn1parse used to extract data from ASN.1 formatted data, and is able to parse our X.509 certificate.
8:d=2 hl=2 l= 3 cons: cont [ 0 ]
10:d=3 hl=2 l= 1 prim: INTEGER :02
13:d=2 hl=2 l= 16 prim: INTEGER
:0E64C5FBC236ADE14B172AEB41C78CB0
... ...
1236:d=4 hl=2 l= 12 cons: SEQUENCE
1238:d=5 hl=2 l= 3 prim: OBJECT :X509v3 Basic Constraints
1243:d=5 hl=2 l= 1 prim: BOOLEAN :255
For modulus (n):
$ openssl x509 -in c1.pem -noout -modulus
Print out all the fields, find the exponent (e):
$ openssl x509 -in c1.pem -text -noout
EIE553 Lab 1 10
$ openssl asn1parse -i -in c0.pem -strparse 4 -out c0_body.bin -noout
$ sha256sum c0_body.bin
The field starting from 。 is the body of the certificate that is used to generate the hash; the field starting 
from @ is the signature block. Their offsets are the numbers at the beginning of the lines. In our case, the 
certificate body is from offset 4 to 1249, while the signature block is from 1250 to the end of the file. For
X.509 certificates, the starting offset is always the same (i.e., 4), but the end depends on the content length 
of a certificate. We can use the -strparse option to get the field from the offset 4, which will give us the 
body of the certificate, excluding the signature block.
Once we get the body of the certificate, we can calculate its hash using the following command:
Step 5: Verify the signature. Now we have all the information, including the CA’s public key, the CA’s 
signature, and the body of the server’s certificate. We can run our own program to verify whether the 
signature is valid or not. Openssl does provide a command to verify the certificate for us, but students are 
required to use their own programs to do so, otherwise, they get zero credit for this task.
4 Submission
You need to submit a detailed lab report, with screenshots, to describe what you have done 
and what you have observed. You also need to provide explanation to the observations that
are interesting or surprising. Please also list the important code snippets followed by 
explanation. Simply attaching code without any explanation will not receive credits.
OCTET STRING
OBJECT 
NULL

請加QQ:99515681  郵箱:99515681@qq.com   WX:codinghelp



 

掃一掃在手機打開當前頁
  • 上一篇:CE 451編程代寫、代做Python語言程序
  • 下一篇:質量流量計的信號輸出方式有哪些?
  • 無相關信息
    合肥生活資訊

    合肥圖文信息
    2025年10月份更新拼多多改銷助手小象助手多多出評軟件
    2025年10月份更新拼多多改銷助手小象助手多
    有限元分析 CAE仿真分析服務-企業/產品研發/客戶要求/設計優化
    有限元分析 CAE仿真分析服務-企業/產品研發
    急尋熱仿真分析?代做熱仿真服務+熱設計優化
    急尋熱仿真分析?代做熱仿真服務+熱設計優化
    出評 開團工具
    出評 開團工具
    挖掘機濾芯提升發動機性能
    挖掘機濾芯提升發動機性能
    海信羅馬假日洗衣機亮相AWE  復古美學與現代科技完美結合
    海信羅馬假日洗衣機亮相AWE 復古美學與現代
    合肥機場巴士4號線
    合肥機場巴士4號線
    合肥機場巴士3號線
    合肥機場巴士3號線
  • 短信驗證碼 目錄網 排行網

    關于我們 | 打賞支持 | 廣告服務 | 聯系我們 | 網站地圖 | 免責聲明 | 幫助中心 | 友情鏈接 |

    Copyright © 2025 hfw.cc Inc. All Rights Reserved. 合肥網 版權所有
    ICP備06013414號-3 公安備 42010502001045

    亚洲国产三级| 日韩成人三级| www.神马久久| 亚洲精品欧美| 香蕉成人av| 国产亚洲欧洲| 久久精品成人| 日韩av中文字幕一区二区三区| 国产第一精品| 91日韩视频| 激情综合网站| 精品无人区麻豆乱码久久久| 国产精品亚洲片在线播放| 91大神在线观看线路一区| 久久先锋影音| 欧美 日韩 国产 一区| 99国产精品久久一区二区三区| 在线成人超碰| 久久影院亚洲| 亚洲精品777| www.youjizz.com在线| 中文在线一区| 欧美一站二站| 精品久久久中文字幕| 亚洲婷婷丁香| 久久中文资源| 日韩国产成人精品| 国产精品蜜月aⅴ在线| 色一区二区三区| 蜜桃久久久久久久| 免费日韩一区二区| 亚洲激情偷拍| 一区三区视频| 欧美女激情福利| 极品少妇一区二区三区| 欧美一区二区三区久久| 日韩av综合| 日韩大片在线免费观看| 国产亚洲第一伦理第一区| 久久久精品国产**网站| 青青草国产成人av片免费| 久久国产免费看| 欧美影院一区| 欧美黄色网络| 久久精品一区二区国产| 美女精品一区二区| 老司机免费视频一区二区三区| 日韩毛片网站| 久久精品xxxxx| 久久精品人人| 日本v片在线高清不卡在线观看| 一区二区91| 日本特黄久久久高潮| 久久夜色电影| 国产一区二区欧美| 日韩av网址大全| 4438全国亚洲精品观看视频| 97精品久久| 99精品美女| 亚洲女同另类| 久久成人精品| 韩日毛片在线观看| 亚洲精品大片| 国产精品红桃| 日韩手机在线| 林ゆな中文字幕一区二区| 在线日韩中文| 亚洲中午字幕| 日韩电影免费在线观看| 日韩三级成人| 欧美激情视频一区二区三区免费| 国产欧美欧美| 北条麻妃在线一区二区免费播放| 天堂网av成人| 国产亚洲精品bv在线观看| caoporn视频在线| 久久不卡日韩美女| 国一区二区在线观看| 日韩有码一区| 久久在线电影| 日韩成人免费| 国产精品久久久久久妇女| 亚洲影视一区| 91精品日本| 女生裸体视频一区二区三区| 色婷婷亚洲mv天堂mv在影片| 99九九久久| 国产精品欧美日韩一区| 红杏一区二区三区| 欧美精品一线| 91精品影视| 成人在线日韩| 久久九九电影| 丝袜a∨在线一区二区三区不卡| 先锋欧美三级| 国产精品一区二区99| 久久激情一区| 91亚洲国产| 欧美精品国产一区二区| 999国产精品一区| 亚洲欧美日韩国产综合精品二区| 日韩精品不卡一区二区| 95精品视频| 亚洲小说欧美另类社区| 亚洲女同av| а天堂中文最新一区二区三区| 大陆精大陆国产国语精品| 亚洲一区二区三区免费在线观看| 蜜桃视频在线网站| 欧美女王vk| 欧美日韩在线网站| 日韩理论片av| 精品视频在线观看免费观看| 精品视频国内| 美女诱惑一区| 欧美国产另类| 九九综合久久| 亚洲aⅴ网站| 欧美三区美女| 久久r热视频| 国内精品久久久久久99蜜桃| 婷婷激情图片久久| 久久精品超碰| 清纯唯美亚洲经典中文字幕| 久久久久免费| 国产aⅴ精品一区二区三区久久| 国产综合激情| 久久国产免费看| 少妇精品导航| 国产三级一区| 精品国产aⅴ| 国产一区二区三区朝在线观看| 精品久久久久久久久久岛国gif| 噜噜噜躁狠狠躁狠狠精品视频| 日韩高清中文字幕一区| 99久精品视频在线观看视频| 欧美一区久久久| 国产精品一区二区中文字幕| 欧美h版在线| 天堂99x99es久久精品免费| 久久xxxx精品视频| 国产欧美亚洲精品a| 老妇喷水一区二区三区| 欧美经典一区| 成人在线国产| 午夜电影一区| 黄毛片在线观看| 成人18夜夜网深夜福利网| 日韩片欧美片| 牛牛精品成人免费视频| 免费成人毛片| 欧洲杯足球赛直播| 91精品福利观看| 午夜亚洲视频| 日韩mv欧美mv国产网站| 日本在线啊啊| 久久久精品性| 亚洲精品四区| 另类av一区二区| 视频二区欧美| 成人四虎影院| 黑人操亚洲人| 中文字幕日韩欧美精品高清在线| 免费日韩av| 日韩中文一区二区| 国产精品蜜月aⅴ在线| 今天的高清视频免费播放成人| 毛片一区二区三区| 丝袜脚交一区二区| 欧美视频四区| 青青草成人在线观看| 久久国产成人| 中文字幕日韩高清在线| 亚洲成人a级片| 女生裸体视频一区二区三区| 国产免费久久| 欧美日韩尤物久久| 亚欧美无遮挡hd高清在线视频 | 色中色综合网| 精品国产91| 亚洲图片小说区| 三级在线看中文字幕完整版| 91精品天堂福利在线观看| 综合天堂av久久久久久久| 在线视频cao| 亚洲小说欧美另类婷婷| 国产精品羞羞答答在线观看| 欧美成人精品三级网站| 天天做综合网| 一区二区精彩视频| 国产精品激情| 日韩激情图片| 国产亚洲在线| 精品大片一区二区| 国产在线不卡一区二区三区| 午夜精品成人av| 天堂av在线一区| 欧美亚洲激情| 亚洲精品aⅴ| 国产剧情一区二区在线观看|